Well, you should definitely keep in mind that this work was done while I was taking Circuits I, so some problems may or may not be solved in a completely sound manner... however, most are, as all the answers that are up here came back as being correct (outside of a few that I may have transcribed incorrectly, as all my original work is done on a dry-erase board). Outside of that, I would stand by my work. Did you have a question regarding any problem in general?
I used some basic algebra (that sounds snarky, but I don't mean to be - I just want you to know where I am going with this).
First, I used Ohm's law to describe the relationship between ix & V1. That gave me
(1) ix = V1/15
Next, I used KCL (Kirchoff's Current Law, wich states that the sum of the current in a node is zero) to give me an equation with V1 & V2 in it. That is where I came up with:
(2) 0 = -45 + V1/15 + V2/25 + (V2-460)/40
I then solved equation 2 to solve for V2 in terms of V1. I made a transcription error, which you will see fixed here:
(3) V2 = (7*V1)/3 + V1 (4) V2 = (10*V1)/3
Now that I know what V2 is in terms of V1, I can go back to equation 2, and replace all of my V2 values with (10/3)*V1.
Thank you so much! I didn't think you would reply. We had not seen this in lecture yet. We went over it today and it all made sense. Your solutions helped me a lot to finish my HW before we even got there in lecture.
are you sure your work is correct?
ReplyDeleteWell, you should definitely keep in mind that this work was done while I was taking Circuits I, so some problems may or may not be solved in a completely sound manner... however, most are, as all the answers that are up here came back as being correct (outside of a few that I may have transcribed incorrectly, as all my original work is done on a dry-erase board). Outside of that, I would stand by my work. Did you have a question regarding any problem in general?
ReplyDeleteNumber 21 is confusing! How do you get V2?
ReplyDeleteI used some basic algebra (that sounds snarky, but I don't mean to be - I just want you to know where I am going with this).
ReplyDeleteFirst, I used Ohm's law to describe the relationship between ix & V1. That gave me
(1) ix = V1/15
Next, I used KCL (Kirchoff's Current Law, wich states that the sum of the current in a node is zero) to give me an equation with V1 & V2 in it. That is where I came up with:
(2) 0 = -45 + V1/15 + V2/25 + (V2-460)/40
I then solved equation 2 to solve for V2 in terms of V1. I made a transcription error, which you will see fixed here:
(3) V2 = (7*V1)/3 + V1
(4) V2 = (10*V1)/3
Now that I know what V2 is in terms of V1, I can go back to equation 2, and replace all of my V2 values with (10/3)*V1.
(5) 0 = -45 + V1/15 + (10/3)*V1/25 + ((10*V1/3)-460)/40
Next, solve equation 5 for V1 (I am assuming that my previous calculations were correct. You should do the calculations yourself to be sure).
(6) V1 = 199.4 V
Plug equation 6 into all the instances of V1 in equation 2:
(7) 0 = -45 + 199.4/15 + V2/25 + (V2-460)/40
Solve for V2:
(8) V2 = 664.7 V
Good luck!!!
Thank you so much! I didn't think you would reply. We had not seen this in lecture yet. We went over it today and it all made sense. Your solutions helped me a lot to finish my HW before we even got there in lecture.
ReplyDelete